Gaseous C2H4 reacts with O2 according to the following equation:

C2H4 (g) + 302 - > 2CO2 + H2O (g)

What volume of oxygen gas at STP is needed to react with 5.75 mol of C2H4?

A) 17.3 L

B) 42.9 L

C) 3.86 x 10^2 L

D) 1.29 x 10^2 L

E) Not enough information is given to solve the problem.

Question

Tabitha Ramos

Chemistry

14 November, 05:43

Gaseous C2H4 reacts with O2 according to the following equation:

C2H4 (g) + 302 - > 2CO2 + H2O (g)

What volume of oxygen gas at STP is needed to react with 5.75 mol of C2H4?

A) 17.3 L

B) 42.9 L

C) 3.86 x 10^2 L

D) 1.29 x 10^2 L

E) Not enough information is given to solve the problem.

+3

Answers (1)

Know the Answer?

Finley Skinner · Answer 1

Each mole of C₂H₄ requires 3 moles of O₂ to react.

5.75 moles of C₂H₄ will require:

3 x 5.75 = 17.25 moles

Each mole of gas occupies 22.4 L at STP.

Liters of gas = 17.25 x 22.4

= 3.86 x 10² L

The answer is C.

Gaseous C2H4 reacts with O2 according to the following equation:C2H4 (g) + 302 - > 2CO2 + H2O (g)What volume of oxygen gas at STP is needed to react with 5.75 mol of C2H4?A) 17.3 LB) 42.9 LC) 3.86 x 10^2 LD) 1.29 x 10^2 LE) Not enough information is given to solve the problem.

Gaseous C2H4 reacts with O2 according to the following equation:

C2H4 (g) + 302 - > 2CO2 + H2O (g)

What volume of oxygen gas at STP is needed to react with 5.75 mol of C2H4?

A) 17.3 L

B) 42.9 L

C) 3.86 x 10^2 L

D) 1.29 x 10^2 L

E) Not enough information is given to solve the problem.