A sample of propane, a component of lp gas, has a volume of 35.3 l at 315 k and 922 torr. what is its volume at stp (r = 0.08206 l • atm/k • mol, 1 atm = 760 torr) ?

Question

Ariel Odonnell

Chemistry

6 February, 07:06

A sample of propane, a component of lp gas, has a volume of 35.3 l at 315 k and 922 torr. what is its volume at stp (r = 0.08206 l • atm/k • mol, 1 atm = 760 torr) ?

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Kierra Salas · Answer 1

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At number of moles the value of PV/T is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1/T1 = P2V2/T2

V2 = P1V1T2 / T1P2

V2 = 922 (35.3) (273.15) / 315 (760)

V2 = 37.13 L