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4 July, 13:41

How many milliliter of a solution of 4.00KI are needed to prepare 250.0mL of 0.760 KI

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  1. 4 July, 13:52
    0
    47.5 mL

    Solving:

    M1 = 4.00 M

    V1 = ?

    M2 = 0.760 M

    V2 = 0.250 L

    ---

    M1 * V1 = M2 * V2

    V1 = (M2 * V2) / M1

    V1 = (0.760 * 0.250) / 4.00

    V1 = (0.190) / 4.00

    V1 = 0.0475 L
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