31) To extend a length of 1.00 inches, 2.54 x 10^8 average sized atoms would have to be placed in a straight line (in other words, 2.54 x 10^8 atoms per 1.00 inches) how many average sized atoms, placed in a straight line, would be required to

form a line extending from the Earth to the moon when the moon is its farthest distance from the

Earth? When the earth and moon are as far apart from each other as they ever get, the distance between the two is 405,696 km

Question

Marisol Valentine

Chemistry

11 February, 05:30

31) To extend a length of 1.00 inches, 2.54 x 10^8 average sized atoms would have to be placed in a straight line (in other words, 2.54 x 10^8 atoms per 1.00 inches) how many average sized atoms, placed in a straight line, would be required to

form a line extending from the Earth to the moon when the moon is its farthest distance from the

Earth? When the earth and moon are as far apart from each other as they ever get, the distance between the two is 405,696 km

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Answers (1)

Know the Answer?

Brett Casey · Answer 1

Here's the conversion factor you need:

1 Kilometer = 39370 inches

So, for your question we want to go 405,696 km ...

405696 km x 39370 inches / 1 km = 15972283464 inches

15972283464 inches x 2.54 x10^8 atoms/1 inch = 4.05 x 10^18 atoms