How many grams of water are required to form 9.00 moles of TiO2 according to the reaction described by

the following equation: TiCl4 + 2H2O → TiO2 + 4HCI.

A. 36 g H2O

B. 324 g H2O

C. 359 g H2O

D. 719 g H2O

324 g of H₂O - Option B.

Explanation:

TiCl₄ + 2H₂O → TiO₂ + 4HCI

1 mol of TiO₂ needed 2 mol of water to be produced.

9 moles of TiO₂ would need 18 mol of water, to be produced (2x9)

1 mol of water weighs 18 g

18 mol of water weigh (18. 18) / 1 = 324 g