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8 February, 11:10

A 3.30 M aqueous solution of LiCl has a density of 1.0736 g/mL. If the total mass of the solution is 66.0 g, what masses of solute and solvent are present

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Answers (2)
  1. 8 February, 11:19
    0
    Mass of solute, LiCl = 8.60g

    Mass of solvent, H₂O = 57.4 g

    Explanation:

    Solution density = Solution mass / Solution volume

    1.0736 g/mL = 66 g / Solution volume

    66 g / 1.0736 g/mL = 61.47 mL

    We know solution's molarity, so with this data we know that 3.30 moles of solute (LiCl) are contained in 1 L of solution (1000 mL)

    Let's make the rule of three:

    1000 mL contain 3.30 moles of LiCl

    61.47 mL would contain (61.47 mL. 3.30 mol) / 1000 mL = 0.203 moles of LiCl

    We can find out the mass of solute with the moles. Let's do it!

    0.203 mol. 42.39 g/mol = 8.60 g of LiCl.

    Total mass = Mass of solvent + Mass of solute

    Let's find out the mass of solvent, to finish the problem

    66 g = Mass of solvent + 8.60 g

    66 g - 8.60 g = Mass of solvent → 57.4 g
  2. 8 February, 11:37
    0
    The solute (LiCl) has a mass of 8.605 grams

    The solvent has a mass of 57.395 grams

    Explanation:

    Step 1: Data given

    Molarity of LiCl = 3.30 M

    Densit = 1.0736 g/mL

    Mass of the solution = 66.0 grams

    Step 2: Calculate volume of LiCl solution

    Volume = mass / density

    Volume = 66.0 grams / 1.0736 g/mL

    Volume = 61.5 mL = 0.0615 L

    Step 3: Calculate moles of LiCl

    Moles = molarity * volume

    Moles = 3.30 M * 0.0615 L

    Moles = 0.203 moles

    Step 4: Calculate mass of LiCl (solute)

    Mass = moles * molar mass

    Mass LiCl = 0.203 moles * 42.39 g/mol

    Mass LiCl = 8.605 grams

    Step 5: Calculate mass solvent

    Mass solvent = mass solution - mass solute

    Mass solvent = 66.0 g - 8.605

    Mass solvent = 57.395

    The solute (LiCl) has a mass of 8.605 grams

    The solvent has a mass of 57.395 grams
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