Ask Question
30 September, 20:08

At a certain temperature this reaction follows second-order kinetics with a rate constant of 0.00317sâ1: 2N2O5 (g) â2N2O4 (g) + O29 (g) Suppose a vessel contains SO3 at a concentration of 1.44M. Calculate the concentration of SO3 in the vessel 0.240 seconds later. You may assume no other reaction is important. Round your answer to 2 significant digits.

+3
Answers (1)
  1. 30 September, 20:13
    0
    [A] = 1.438M = 1.4M (Two s. f)

    Explanation:

    Rate constant, k = 0.00317

    Initial Concentration, [A]o = 1.44M

    Final Concentration, [A] = ?

    Time, t = 0.240 s

    Since this is a second order reaction, the formula for this is given as;

    1 / [A] = 1 / [A]o + kt

    1 / [A] = 1 / 1.44 + (0.00317 * 0.240)

    1 / [A] = 0.6944 + 0.0007608

    1 / [A] = 0.6952

    [A] = 1.438M = 1.4M (Two s. f)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “At a certain temperature this reaction follows second-order kinetics with a rate constant of 0.00317sâ1: 2N2O5 (g) â2N2O4 (g) + O29 (g) ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers