Given the equation 2CH4 S8 - -> 2CS2 4H2S Calculate the moles of H2S produced when 1.5 mol S8 is used.

6.0 moles of H₂S are produced.

Explanation:

Let's consider the following balanced equation.

2 CH₄ + S₈ → 2 CS₂ + 4 H₂S

The molar ratio of S₈ to H₂S is 1 mol S₈: 4 mol H₂S. The moles of H₂S produced when 1.5 mol of S₈ react are:

1.5 mol S₈ * (4 mol H₂S / 1 mol S₈) = 6.0 mol H₂S

6.0 moles of H₂S are produced, when 1.5 mol of S₈ react.