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5 October, 23:27

Assign the oxidation number for (NH4) 3PO4

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  1. 5 October, 23:41
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    N (-3)

    N (+1)

    P (+5)

    O (-2)

    -3*3 + (+1) * 12 + (+5) + (-2) * 4=-9+12+5-8 = 0 - the sum of oxidation number in the molecule should be equal zero.
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