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28 June, 15:14

A certain reaction has the form aA → bB. At a particular temperature and [A]0 = 2.80 * 10-3 molar, data was collected of concentration versus time for this reaction. A plot of 1/[A]t versus time resulted in a straight line with a slope value of 3.60 * 10-2 M-1s-1. What is the concentration of A after 300 seconds?

a. 2.80 * 10-3 molar

b. 2.72 * 10-3 molar

c. 2.60 * 10-3 molar

d. 3.60 * 10-2 molar

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Answers (1)
  1. 28 June, 15:22
    0
    If the plot of 1/[A] versus time shows a constant slope, this means it is a second-order reaction. The equation would be:

    1/[A] - 1/[A]0 = kt

    1/[A] - 1/0.0028 = 0.036 (300)

    1/[A] = 0.00272 = 2.72 x 10^-3 M

    This is equivalent to choice B.
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