What is the concentration of nitrate ion in a 425 ml solution containing 32.0 g of Mg (NO3) 2 (M = 148.3)

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Solomon Powell

Chemistry

20 August, 07:35

What is the concentration of nitrate ion in a 425 ml solution containing 32.0 g of Mg (NO3) 2 (M = 148.3)

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Marissa · Answer 1

Supposing complete ionization:

Mg (NO3) 2 → Mg{2+} + 2 NO3{-}

(32.0 g Mg (NO3) 2) / (148 g Mg (NO3) 2/mol) x (2 mol NO3{-} / 1 mol Mg (NO3) 2) / (0.425 L) = 1.02 mol/L NO3{-}