A sample of Al2O3 decomposed to pure aluminum and oxygen. After decomposition, 29.0 moles of Al were recovered. How many moles of Al2O3 were decomposed?

Question

Memphis Jacobson

Chemistry

15 April, 12:16

A sample of Al2O3 decomposed to pure aluminum and oxygen. After decomposition, 29.0 moles of Al were recovered. How many moles of Al2O3 were decomposed?

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Konner Hayes · Answer 1

The decomposition of Al2O3 to form pure aluminum (Al) along with the release of oxygen (O2) gas can be represented by the following chemical reaction:

2Al2O3 → 4Al + 3O2

Based on the reaction stoichiometry:

2 moles of aluminum oxide decomposes to form 4 moles of pure aluminum

Therefore, if 29.0 moles of aluminum is recovered, then the moles of aluminum oxide required will be:

= 29.0 moles Al * 2 moles Al2O3/4 moles Al

= 14.5 moles of Al2O3