If the molar mass of calcium hydroxide (Ca (OH) 2) is 74.1 g/mol, how many grams of calcium hydroxide are required to prepare 2.00 liters of 0.60 M calcium hydroxide

88.92 grams of Ca (OH) ₂ are required

Explanation:

Molarity means mol/L, so 0.6 M are the moles of solute in 1 L of solution.

In 2 L, we 'll have the double of moles, 1.2

Mol. molar mass = grams

1.2 mol. 74.1 g/m = 88.92 grams of solute