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6 November, 18:55

What is the molarity of a potassium triiodide solution, KI3 (aq), if 30.00 mL of the solution is required to completely react with 25.00 mL of a 0.500 M thiosulfate solution, K2S2O3 (aq)

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  1. 6 November, 18:58
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    The molarity is 0.203 M

    Explanation:

    Using the formula C (oxi) x V (oxi) / [C (red) x V (red) ] = N (oxi) / N (red)

    Where oxi and red means reducing agent and oxidising agent respectively.

    C = Concentration, V = Volume and N = number of moles.

    C (oxi) = 0.5 M

    V (oxi) = mL

    C (red) = ?

    V (red) = 30mL

    Equation of reaction = 2K2S2O3 + KI3 = K2S4O6 + 3KI

    so N (red) = 1, N (oxi) = 2

    from the equation above,

    C (red) = 0.5 x 25 x 1 / (2 x 30)

    = 0.203 M.
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