You have prepared a saturated solution of x at 20∘c using 37.0 g of water. how much more solute can be dissolved if the temperature is increased to 30∘c?

The solubility of the solute should be given here which should be as follows:

temperature at 20 degrees C : solubility 11.0 g X / 100 g H2O

temperature at 30 degrees C : solubility 23.0 g X / 100 g H2O

To determine how much more of the solute can be added to the solution when the temperature is increased, we calculate the total mass of the solute that can be dissolved in the solution at 30 degrees Celsius.

Mass of X = 23.0 g X / 100 g H2O (37.0 g H2O) = 8.51 g X at T=30 degrees Celsius

Then, we calculate also the mass of X at 20 degrees Celsius

Mass of X = 11.0 g X / 100 g H2O (37.0 g H2O) = 4.07 g X

Mass of X that can be added after increasing the temperature = 8.51 - 4.07 = 4.44 g of X