A gas at 155 kPa and standard temperature has an initial volume of 1.00 L. The pressure of the gas rises to 500 kPa as the temperature also rises to 135°C. What is the new volume?

2.16 L

0.463 L

0.207 L

4.82 L

In the combined gas equation, (P1V1) / T1 = (P2V2) T2, where P1 is the initial pressure, V1 the initial volume, T1 the initial temperature, P2 is the final pressure, V2 the final volume, T2 the final temperature,

substituting for the values: (155kPa * 1.00L) / 273K = (500kPA * V2) / 408K

V2 = (155kPa*1.00L*408K) / (273K*500kPa)

= 0.463L