If a saturated solution of nh4no3 at 75 °c is cooled to 15 °c, how many grams of solute will separate if the quantity of the solvent is 127 g? answers

Solubility of ammonium nitrate in water at 15°C is 173 g.

Solubility of ammonium nitrate in water at 75°C is 499 g.

m (water) = 127 g.

15°C:

173 g : 100 g = m (NH₄NO₃) : 127 g.

m (NH₄NO₃) = 219,71 g.

75°C:

499 g : 100 g = m (NH₄NO₃) : 127 g.

m (NH₄NO₃) = 633,73 g.

m (NH₄NO₃) = 633,73 g - 219,71.

m (NH₄NO₃) = 414,02 g.