How many moles of compound are present in 33 grams of KMnO4?

Answer in units of mol.

Answer: 0.21 mole

Explanation:

Atomic mass of Potassium, K = 39.1g/mol

Atomic mass of Manganese, Mn = 54.9g/mol

Atomic mass of Oxygen, I = 16g/mol

First find the molar mass of KMnO4, that is

KMnO4 = 39.1+54.9 + (16) 4

Molar mass of KMnO4 = 158g/mol

Hence,

1 mole of KMnO4 = 158g

Let x mole of KMnO4 = 33g

x = 33/158 mole

x = 0.21 mole