Ask Question
25 October, 02:19

Calculate the amount of work done, in joules, when 2.5 mole of H2O vaporizes at 1.0 atm and 25°C. Assume the volume of liquid H2O is negligible compared to that of vapor. (1 L·atm = 101.3 J)

+1
Answers (1)
  1. 25 October, 02:29
    0
    6.195 x 10 3 J oule

    Explanation:

    all given values

    Temperature = 25 + 273 = 298K

    Pressure = 1 atm

    ideal gas constant = R=0.0821 L. atm/K/mol

    number of moles n = 2.5

    volume = ?

    using ideal gas equation

    PV=nRT

    for volume V=nRT/P

    =2.5*.0821*298/1

    =61.16 L

    As the direction of work done is opposite to the direction of motion so work done will be negative

    W=-PV

    =-1atm * 61.16 L

    =101.3 * 61.61

    = - 6195.96 J

    = 6.195 x 10 3 J
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Calculate the amount of work done, in joules, when 2.5 mole of H2O vaporizes at 1.0 atm and 25°C. Assume the volume of liquid H2O is ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers