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ChemistryChemistry
11 December, 12:40

The charges on two metallic balls are 5.0 and 7.0 coulombs respectively. They are kept 1.2 meters apart. What is the force of interaction between the two?

(k = 9.0 * 109 newton·meters2/coulomb2)

2.2 * 1011 newtons

4.1 * 10-7 newtons

5.0 * 1011 newtons

7.0 * 10-7 newtons

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Answers (1)
  1. 11 December, 12:45
    0
    Using Coulomb's Law, which states that F = kq1q2/r^2,

    where q1 and q2 are the charges of the objects, and r is the distance between them,

    we substitute:

    F = (9.0x10^9) (5.0) (7.0) / 1.2²

    F = 2.1875x10^11 N

    Answer is 2.2 x 10^11 N.
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Home » Chemistry » The charges on two metallic balls are 5.0 and 7.0 coulombs respectively. They are kept 1.2 meters apart. What is the force of interaction between the two? (k = 9.0 * 109 newton·meters2/coulomb2) 2.2 * 1011 newtons 4.1 * 10-7 newtons 5.
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