What is the minimum mass of ice at 0.0 C that must be added to 1.00 kg of water to cool the water from 28.0 C to 12.0 C? (Heat of fusion = 333 J/g; specific heat capacities: ice = 2.06 J/gK, liquid water = 4.184 J/gK)

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9 May, 04:25

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Belen Hansen · Answer 1

(4.184 J/g·°C) x (1000 g) x (28.0 - 12.0) °C = 66944 J required

(66944 J) / ((333 J/g) + ((4.184 J/g·°C) x (12.0 - 0) °C)) = 175 g ice