There are four naturally occurring isotopes of the element chromium. The relative abundance of each is 50Cr - 4.345% 49.946044 amu 52Cr - 83.789% 51.940508 amu 53Cr - 9.501% 52.940649 amu 54Cr - 2.365% 53.93880 amu Find the average atomic mass of chromium. A. 52.061 amu B. 52.978 amu C. 51.996 amu D. 53.2503 amu

Question

Jamiya Scott

Chemistry

15 May, 03:05

There are four naturally occurring isotopes of the element chromium. The relative abundance of each is 50Cr - 4.345% 49.946044 amu 52Cr - 83.789% 51.940508 amu 53Cr - 9.501% 52.940649 amu 54Cr - 2.365% 53.93880 amu Find the average atomic mass of chromium. A. 52.061 amu B. 52.978 amu C. 51.996 amu D. 53.2503 amu

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Amaris Graves · Answer 1

The average molar mass of an atom is equal to the summation of the molar mass of the isotopes multiplied by their relative abundance. In this case, we substitute and use the formula:

MW ave = 49.946044 amu*0.04345 + 51.940508 amu * 0.83789 + 52.940649 amu * 0.09501 + 53.93880 amu * 0.02365 = 51.966 amu.

Answer is C