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29 March, 12:20

11.5 grams of sodium metal are placed in a container with excess chlorine gas. Once the reaction is complete, 29.0 grams of sodium chloride are measured. What mass, in grams, of chlorine gas reacted?

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  1. 29 March, 13:23
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    17.6 g of chlorine gas reacted.

    Explanation:

    1) Chemical equation:

    2Na + Cl₂ (g) → 2NaCl (s)

    2) Mole ratios:

    2 mol Na : 1 mol Cl₂ : 2 mol NaCl

    3) Number of moles of sodium chloride (NaCl) measured (produced):

    Number of moles = mass in grams / molar mass

    Molar mass of NaCl = 58.44 g/mol

    Number of moles of NaCl = 29.0 g / 58.44 g/mol = 0.496 mol

    4) Number of moles of chlorine gas (Cl₂) reacted:

    From the stoichiometric mole ratios:

    1 mol Cl₂ / 2 mol NaCl = x / 0.496 mol NaCl

    x = 0.496 mol NaCl / 1 mol Cl₂ / 2 mol NaCl = 0.248 mol Cl₂.

    5) Convert 0.248 mol Cl₂ into mass in grams:

    mass in grams = molar mass * number of moles molar mass of Cl₂ = 70.9 g/mol mass in grams = 70.9 g/mol * 0.248 mol = 17.6 g ← answer
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