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20 December, 04:32

If an equal quantity of heat is transferred to 10.0 g samples of liquid water (C = 4.184 J/g°C), concrete (C = 0.88 J/g°C), asphalt (C = 0.920 J/g°C), glass (C = 0.84 J/g°C), and iron (C = 0.448 J/g°C), rank the final temperatures of the samples from least to greatest.

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  1. 20 December, 04:42
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    The ranking is given as; Water > Asphalt > Concrete > glass > Iron

    Explanation:

    The trick in solving this question is to assume a constant heat value; in this case i'll be choosing 100 J. Use this value to solve for the temperature difference. from that we can be able to rank the samples in order of their temperatures.

    The formular to be used here is the;

    H = MCΔT

    Where;

    H = Heat

    M = Mass

    C = Heat Capacity

    ΔT = Temperature difference

    ΔT = H/MC

    In water;

    ΔT = 100 / (10 * 4.184) = 2.39K

    In Concrete;

    ΔT = 100 / (10 * 0.88) = 11.36K

    In asphalt;

    ΔT = 100 / (10 * 0.920) = 10.87K

    In glass;

    ΔT = 100 / (10 * 0.84) = 11.9K

    In iron;

    ΔT = 100 / (10 * 0.448) = 22.3K

    The samples with least temperature difference would have final temperatures and vice versa.

    Our ranking is the given as; Water > Asphalt > Concrete > glass > Iron
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