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30 November, 11:35

A gas at 155 Kpa and 25 degrees celsius has a volume of 1 L. The pressure increases to 605 kPa as the temperature is raised to 125 degrees Celsius what is the new volume?

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  1. 30 November, 11:48
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    The answer to your question is V2 = 0.34 l

    Explanation:

    Data

    Pressure 1 = P1 = 155 kPa

    Temperature 1 = T1 = 25°C = 298°K

    Volume 1 = V1 = 1 l

    Pressure 2 = P2 = 605 kPa

    Temperature 2 = T2 = 125°C = 398°K

    Volume 2 = V2 = ?

    Process

    To solve this problem use the Combined gas law.

    P1V1/T1 = P2V2/T2

    -Solve for V2

    V2 = P1V1T2 / T1P2

    -Substitution

    V2 = (155) (1) (398) / (298) (605)

    -Simplification

    V2 = 61690 / 180290

    -Result

    V2 = 0.34 l
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