345.2 grams of cl2 gas occupy what volume at stp

The volume occupied by 345.2 g of Cl2 at STP is calculated as below

find the moles of Cl2 used

moles = mass/molar mass

molar mass of Cl2=35.5 x2 = 71g/mol

moles = 345.2 g / 71 g/mol = 4.86 moles

at STP 1 mole = 22.4 liters

what about 4.86 moles

by cross multiplication

4.86moles/1mole x22.4 liters = 108.86 liters of Cl2