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22 April, 04:26

The element antimony exists in nature as two isotopes: has a mass of 120.9038 u and has a mass of 122.9042 u. The average atomic mass of antimony is 121.76 u. Calculate the relative abundance of the two antimony isotopes.

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  1. 22 April, 04:54
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    The percentage relative abundances of isotopes are 56.20% and 43.80%

    Explanation: Relative atomic mass of an element is calculated by getting the average mass of all the atoms of an element relative to 1/12th the mass of carbon-12 atom. It is calculated by getting the average of the product of relative abundance by the mass of each atom.

    In this case;

    Average atomic mass = 121.76 u

    Mass of the first isotope = 120.9038

    Mass of the second isotope = 122.9042

    Assuming the relative abundances are;

    1st isotope = x %

    2nd isotope = (100-x) %

    Therefore;

    121.76 = ((120.9038x) + (100-x) (122.9042)) : 100

    12176 = 120.9038x + 12290.42 - 122.9042x

    -114.42 = - 2.0004x

    x = 56.20%

    100-x = 43.80%

    Therefore, the percentage relative abundances of isotopes are 56.20% and 43.80%
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