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25 September, 21:14

The molality of calcium chloride (CaCl2) in an aqueous solution is 2.46 m. What is mole fraction of the solute?

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  1. 25 September, 21:29
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    Given that CaCl2 = 2.46 m

    Therefore 2.46 mole of CaCl2 present in 1.00 g of solution

    Mass of 2.46 mole CaCl2 = number of mole * molar mass

    = 2.46 mole * 110.98 g/mol

    = 273.01 g

    Mass of water or solvent = mass of solution - mass of solute

    = 1000 g - 273.01 g

    = 726.99 g

    Mole of water = amount in g / molar mass

    = 726.99 g/18.02 g / mole

    = 40.34 moles

    Mole fraction of CaCl2 = number of mole of CaCl2 / total moles

    = 2.46 / 2.46+40.34

    = 2.46/42.8

    = 0.057
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