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7 September, 02:30

determine the specific heat of a material if a 35g sample absorbed 96 J as it was heated from 293 K to 313 K?

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  1. 7 September, 02:48
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    0.137 J/g*C

    Explanation:

    Cp = k-273.15

    T1 = 293-273.15 = 19.85 C

    T2 = 313 - 273.15 = 39.85 C

    DeltaT = T2-T1 = 20 C

    96/35x20 = 0.137 J/g*C

    the "C" is supposed to be Celsius

    don't ask me to further explain what you already see here
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