determine the specific heat of a material if a 35g sample absorbed 96 J as it was heated from 293 K to 313 K?

0.137 J/g*C

Explanation:

Cp = k-273.15

T1 = 293-273.15 = 19.85 C

T2 = 313 - 273.15 = 39.85 C

DeltaT = T2-T1 = 20 C

96/35x20 = 0.137 J/g*C

the "C" is supposed to be Celsius

don't ask me to further explain what you already see here