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5 July, 22:27

Balance the following Equation:

___Zn + ___HCl - -> ___ZnCl2 + ___H2

50g of zinc are reacted with 50g of hydrogen chloride. What is the excess reactant?

A: HCl

B: H2

C: Zn

D: ZnCl2

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Answers (1)
  1. 5 July, 22:57
    0
    Zn is the excess reactant (0.079 moles in excess)

    Option C is correct

    Explanation:

    Step 1: Data given

    Mass of Zinc (Zn) = 50.0 grams

    Mass of Hydrogen chloride (HCl) = 50.0 grams

    atomic mass Zn = 65.38 g/mol

    Molar mass HCl = 36.46 g/mol

    Step 2: The balanced equation

    Zn + 2HCl → ZnCl2 + H2

    step 3: Calculate moles

    Moles = mass / molar mass

    Moles Zn = 50.0 grams / 65.38 g/mol

    Moles Zn = 0.764 moles

    Moles HCl = 50.0 grams / 36.46 g/mol

    Moles HCl = 1.37 moles

    Step 4: Calculate limiting reactant

    For 1 mol Zn we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

    HCl is the limiting reactant. It will completely be consumed (1.37 moles)

    Zn is in excess. There will react 1.37/2 = 0.685 moles

    There will be 0.764 - 0.685 = 0.079 moles in excess
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