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11 January, 10:47

Consider the following reaction, equilibrium concentrations, and equilibrium constant at a particular temperature. Determine the equilibrium pressure of H2. D2 (g) + H2 (g) ⇌ 2 HD (g) Kp = 1.80 P (D2) eq = 1.1 * 10-3 atm P (HD) eq = 2.7 * 10-3 atm

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  1. 11 January, 10:58
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    1.4 * 10^-3

    Explanation:

    The equilibrium expression can be written as follows:

    Keq = P [HD]^2/[ P[H2] * P[D2]]

    Where P is pressure

    1.80 = (2.7 * 10^-3) ^2 / (1.1 * 10^-3 * P[H2])

    P[H2] = [2.7 * 10^-3]^2 / [1.8 * 1.1 * 10^-3]

    P[H2] = 1.4 * 10^-3 atm
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