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31 May, 07:22

Boyle's law relates the volume and pressure of an ideal gas at two different conditions as V1P1 = V2P2. If the volume of an ideal gas is 2 L at 3 atm, what volume is it at 4 atm?

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  1. 31 May, 07:28
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    (2) (3) / V (4)

    6 = V2 (4)

    6/4 = V2

    V2=1.5 litera
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