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23 December, 17:15

Calculate how much 95% ethyl alcohol will be required to dissolve 0.75 g of sulfanilamide at 78°c

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  1. 23 December, 18:00
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    95% ethyl alcohol

    Mass of sulfanilamide = 0.75 g = 750 mg

    Temperature = 78 c

    Solubility of sulfanilamide in 95% ethyl alcohol at 78°C is 210 mg/mL.

    (210 mg) / (1 mL) = (300 mg) / (x mL) = > x = 300 / 210 = > x 1.43 mL.
  2. 23 December, 18:58
    0
    Missing question: sulfanilamide has a solubility in 95% ethanol of 210 mg/ml at 78 degree Celsius.

    m (sulfanilamide) = 0,75 g = 0,75 · 1000 = 750 mg.

    210 mg : 1 ml = 750 mg : V (ethyl alcohol).

    210 mg · V (ethyl alcohol) = 750 ml · mg.

    V (ethyl alcohol) = 3,57 ml.

    Answer is: 3,57 ml of 95% ethyl alcohol will be required.
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