Calculate how much 95% ethyl alcohol will be required to dissolve 0.75 g of sulfanilamide at 78°c

Missing question: sulfanilamide has a solubility in 95% ethanol of 210 mg/ml at 78 degree Celsius.

m (sulfanilamide) = 0,75 g = 0,75 · 1000 = 750 mg.

210 mg : 1 ml = 750 mg : V (ethyl alcohol).

210 mg · V (ethyl alcohol) = 750 ml · mg.

V (ethyl alcohol) = 3,57 ml.

Answer is: 3,57 ml of 95% ethyl alcohol will be required.

95% ethyl alcohol

Mass of sulfanilamide = 0.75 g = 750 mg

Temperature = 78 c

Solubility of sulfanilamide in 95% ethyl alcohol at 78°C is 210 mg/mL.

(210 mg) / (1 mL) = (300 mg) / (x mL) = > x = 300 / 210 = > x 1.43 mL.