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8 September, 15:34

If 28.64g of N2 reacts with 8.42g of H2 to produce NH3. What is the limiting reactant

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  1. 8 September, 15:36
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    nitrogen is limiting reactant

    Explanation:

    Given data;

    Mass of nitrogen = 28.64 g

    Mass of hydrogen = 8.42 g

    Limiting reactant = ?

    Solution:

    Chemical equation:

    N₂ + 3H₂ → 2NH₃

    Number of moles of nitrogen:

    Number of moles = mass / molar mass

    Number of moles = 28.64 g / 28 g/mol

    Number of moles = 1.02 mol

    Number of moles of hydrogen:

    Number of moles = mass / molar mass

    Number of moles = 8.42 g / 2 g/mol

    Number of moles = 4.21 mol

    Now we compare the moles ammonia with hydrogen and nitrogen

    N₂ : NH₃

    1 : 2

    1.02 : 2/1 * 1.02 = 2.04 mol

    H₂ : NH₃

    3 : 2

    4.21 : 2/3*4.21 = 2.8 mol

    The number of moles of ammonia produced by nitrogen are less so it will limiting reactant.
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