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6 January, 18:01

The relative atomic mass of boron 10.2. if the element occurs in two isotopic forms, boron-10 and boron-11, what are their geometrical abundances?

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  1. 6 January, 18:25
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    The correct answer for the question that is being presented above is this one:

    Boron consists of two isotopes, boron-10 and boron-11.

    Given that its relative atomic mass is 10.2

    Find the abundance of each isotope.

    Let y/100 = the abundance of copper-10

    and (100 - y) / 100 = the abundance of copper-11

    10.2 = (y/100 x 10) + [ (100 - y) / 100 x 11]

    10.2 = 10y/100 + 1100/100 - 11y/100

    1020 = 10y + 1100 - 11y

    -80 = - y

    y = 80

    Abundance of boron-10 = 10/100 = 10%

    Abundance of boron-11 = 100 - 10 = 90%
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