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5 June, 08:46

a gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressute of 2.1 atm. what is he partial pressure of gas Y?

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Answers (2)
  1. 5 June, 08:54
    0
    The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.

    The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an

    individual gas in a mixture and n is total moles of the gas mixture. We

    know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in

    total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate

    the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole

    fraction of gas Y (x) and the total pressure (P) to calculate the

    partial pressure of gas Y (P1) : x = P1/P. P1 = x * P. If x = 0.75 and P =

    2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =

    1.6 atm.
  2. 5 June, 09:11
    0
    this would equal 1.6 atm
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