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13 October, 03:51

A 10.0 L balloon contains helium gas at a pressure of 655 mmHg. What is the final pressure, in millimeters of mercury, if the final volume is 13.8 L?

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  1. 13 October, 04:10
    0
    474.64mmHg

    Explanation:

    From the question given, we obtained the following:

    V1 = 10L

    P1 = 655mmHg

    V2 = 13.8L

    P2 = ?

    P1V1 = P2V2

    10 x 655 = P2 x 13.8

    Divide both side by the coefficient P2 i. e 13.8

    P2 = (10 x 655) / 13.8

    P2 = 474.64mmHg

    Therefore, the new pressure will be 474.64mmHg
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