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3 October, 17:52

What is the pressure of 1.9 mols of nitrogen gas in a 9.45 L tank and at a temperature of 228 K

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  1. 3 October, 18:05
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    P = 3.8 Atm = 2900 mmHg (2 sig. figs.)

    Explanation:

    PV = nRT = > P = nRT/V = (1.9 moles) (0.08206LAtm/molK) (228K) / 9.45L = 3.76 ~ 3.8 Atm x 760mmHg/Atm = 2888 mmHg ~ 2900 mmHg (2 sig. figs.)
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