A solution is prepared by mixing 50.0 mL of ethanol with 300.0 mL of water. What is the volume percent of ethanol in this solution? Assume volumes are additive.

Question

Theodore Valentine

Chemistry

14 March, 18:14

A solution is prepared by mixing 50.0 mL of ethanol with 300.0 mL of water. What is the volume percent of ethanol in this solution? Assume volumes are additive.

+2

Answers (1)

Know the Answer?

Ezequiel Mckay · Answer 1

The answer to your question is 14.3 %

Explanation:

Data

volume of ethanol = 50 ml

volume of water = 300 ml

volume percent = ?

Formula

Percent by volume = (volume of solute/volume of solution) x 100

Volume of solute = 50 ml

volume of solution = 300 + 50 = 350

Substitution

Percent by volume = (50/350) x 100

Simplification and result

Percent by volume = 14.3 %