Considering the law of conservation of mass, if 56 g samples of solid iron (Fe) reacts with 24 g of oxygen (O2), how many grams of Iron Oxide (FeO) are obtained?

62_grams of FeO

Explanation:

Molar mass of Fe = 55.845_g/mol

Molar mass of O2 = 15.999_g/mol

From law of conservation of mass

2 moles of Fe combines with one mole of O2 to form 2 moles of FeO

Number of moles of Fe and O2 present = mass / (molar mass) = 56/55.845~1

and 24/16 = 1.1.5

Therefore

1 part of Fe will react with 0.5 part of one mole of O2

which is 54_g of Fe reacts with 8_g to form 54+8 = 62_grams of FeO