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20 August, 03:43

Considering the law of conservation of mass, if 56 g samples of solid iron (Fe) reacts with 24 g of oxygen (O2), how many grams of Iron Oxide (FeO) are obtained?

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  1. 20 August, 03:47
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    62_grams of FeO

    Explanation:

    Molar mass of Fe = 55.845_g/mol

    Molar mass of O2 = 15.999_g/mol

    From law of conservation of mass

    2 moles of Fe combines with one mole of O2 to form 2 moles of FeO

    Number of moles of Fe and O2 present = mass / (molar mass) = 56/55.845~1

    and 24/16 = 1.1.5

    Therefore

    1 part of Fe will react with 0.5 part of one mole of O2

    which is 54_g of Fe reacts with 8_g to form 54+8 = 62_grams of FeO
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