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20 December, 23:52

Given the lattice energy of kcl = 699 kj/mol, the ionization energy of k = 419 kj/mol and the electron affinity of cl = - 349 kj/mol, calculate the δh o for the reaction: k (g) + cl (g) → kcl (s)

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  1. 21 December, 00:21
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    K - - - > K⁺ = Ionization energy

    Cl - - - > Cl⁻ = Electron affinity

    delta H = Lattice energy + Ionization energy of K + Electron affinity of Cl

    Lattice energy is taken as negative here

    delta H = - 699 + 419 - 349 = - 629 KJ
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