Reacting 35.4 ml of 0.220 m agno3 with 52.0 ml of 0.420 m k2cro4 results in what mass of solid formed

Question

Cristopher Bruce

Chemistry

27 August, 23:22

Reacting 35.4 ml of 0.220 m agno3 with 52.0 ml of 0.420 m k2cro4 results in what mass of solid formed

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Jabari Herman · Answer 1

Answer is: 1.29 grams of solid formed.

Chemical reaction: 2AgNO₃ (aq) + K₂CrO₄ (aq) → Ag₂CrO₄ (s) + 2KNO₃ (aq).

n (AgNO₃) = c (AgNO₃) · V (AgNO₃).

n (AgNO₃) = 0.220 M · 0.0351 L.

n (AgNO₃) = 0.0078 mol; limiting reactant.

n (K₂CrO₄) = 0.420 M · 0.052 L.

n (K₂CrO₄) = 0.022 mol.

From chemical reaction: n (AgNO₃) : n (Ag₂CrO₄) = 2 : 1.

n (Ag₂CrO₄) = 0.0078 mol : 2.

n (Ag₂CrO₄) = 0.0039 mol.

m (Ag₂CrO₄) = 0.0039 mol · 331.73 g/mol.

m (Ag₂CrO₄) = 1.29 g.