Look up the density of n-butyl chloride (1-chlorobutane). Assume that this alkyl halide was prepared instead of the bromide. Decide whether the alkyl chloride would appear as the upper or the lower phase at each stage of the separation procedure: after the reflux, after the addition of water, and after the addition of sodium bicarbonate.

Question

Darian Lozano

Chemistry

9 June, 10:28

Look up the density of n-butyl chloride (1-chlorobutane). Assume that this alkyl halide was prepared instead of the bromide. Decide whether the alkyl chloride would appear as the upper or the lower phase at each stage of the separation procedure: after the reflux, after the addition of water, and after the addition of sodium bicarbonate.

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Answers (1)

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Adyson Casey · Answer 1

See explanation below

Explanation:

First, you need to know the density of each compound in order to know this.

The density of 1-chlorobutane is 0.88 g/mL,

The density of water is 1 g/mL

The density of sodium bicarbonate is 2.2 g/cm3.

therefore, the one that has a greater density will always go at the lower phase.

In this case, after the reflux, it will stay in the lower phase, basically because you don't have another solvent with a greater density than the butane.

After adding water, it will be in the upper phase, water has a greater density.

After adding bicarbonate, it will be in the upper phase too.