How many lithium ions are present in 30.0 ml of 0.600 m li2co3 solution?

First; use the relationship of molarity and moles/liter to find the moles of the solution.

so 0.600M * 0.030L = 0.018 moles

Then use the mole to mole ratio of lithium to lithium carbonate

0.18 * (2 Li : 1 Li2CO3) = 0.036

and then multiply by Avogadro's number to find the ions of lithium

0.036 moles * (6.022*10^{23}) = 2.167 * 10∧22 ions Li