17. If 3.25 g of Na2CO3 is used, how many grams of CaCO3 can be

made?

Mass of CaCO₃ = 3 g

Explanation:

Given dа ta:

Mass of sodium carbonate = 3.25 g

Mass of calcium carbonate produced = ?

Solution:

Chemical equation:

CaCl₂ + Na₂CO₃ → CaCO₃ + 2NaCl

Moles of Na₂CO₃:

Number of moles = mass / molar mass

Number of moles = 3.25 g / 106 g/mol

Number of moles = 0.03 mol

Now we will compare the moles of sodium carbonate with calcium carbonate.

Na₂CO₃ : CaCO₃

1 : 1

0.03 : 0.03

Mass of calcium carbonate:

Mass = number of moles * molar mass

Mass = 0.03 mol * 100 g/mol

Mass = 3 g