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19 December, 22:09

17. If 3.25 g of Na2CO3 is used, how many grams of CaCO3 can be

made?

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Answers (1)
  1. 19 December, 22:22
    0
    Mass of CaCO₃ = 3 g

    Explanation:

    Given dа ta:

    Mass of sodium carbonate = 3.25 g

    Mass of calcium carbonate produced = ?

    Solution:

    Chemical equation:

    CaCl₂ + Na₂CO₃ → CaCO₃ + 2NaCl

    Moles of Na₂CO₃:

    Number of moles = mass / molar mass

    Number of moles = 3.25 g / 106 g/mol

    Number of moles = 0.03 mol

    Now we will compare the moles of sodium carbonate with calcium carbonate.

    Na₂CO₃ : CaCO₃

    1 : 1

    0.03 : 0.03

    Mass of calcium carbonate:

    Mass = number of moles * molar mass

    Mass = 0.03 mol * 100 g/mol

    Mass = 3 g
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