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20 December, 01:36

A cord is used to vertically lower an initially stationary block of mass m kg at a constant downward acceleration of g/4. the block has fallen a distance

d. (use any variable or symbol stated above as necessary.) (a) find the work done by the cord's force on the block. wf = 3mgd 4 incorrect: your answer is incorrect. (b) find the work done by the weight of the block. wg = (c) find the kinetic energy of the block. k = (d) find the speed of the block. v =

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  1. 20 December, 02:01
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    (a) We know that work is the product of Force and Distance so: (in this case Distance is negative since going down so - d)

    work = force * distance

    work = M * (g - g/4) * - d

    work = - 3Mgd/4

    (b) The work by the weight of the block is simply:

    work = Mgd

    (c) The kinetic energy is simply equivalent to the net work, therefore:

    KE = net work

    KE = Mgd/4

    (d) The velocity is:

    v = √ (2*KE/M)

    Plugging in the value of KE from c:

    v = √ (2*Mgd / 4M)

    v = √ (gd / 2)
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