Determine the celsius temperature of 2.49 mol of gas contained in a 1.00 l vessel

= - 266.24°C

Explanation:

According to ideal gas law;

PV = nRT, where P is pressure, V is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature.

PV = nRT

T = PV / (nR)

= 143 kPa * (1atm/101.325 kPa) * 1.00L / (2.49 mol * 0.08206 Latm/molK)

= 6.91 K

= - 266.24°C