How many grams of oxygen are required too burn 8.8g of c3h8?

From the balanced equation:

1mol C3H8 requires 5mol O2 for combustion

Molar mass C3H8 = 44g/mol

8.8g C3H8 = 8.8/44 = 0.2mol C3H8

This will require 5*0.2 = 1.0mol O2

Molar mass O2 = 32g/mol

Therefore 32g of O2 required.