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25 September, 02:05

What is the molality of a solution made by dissolving 50.00 g of glucose, C6H12O6, in 500.0 g water. Give your answer to 3 significant figures.

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  1. 25 September, 02:15
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    m = 0.5556 mol/kg

    Explanation:

    The molality of any solution is calculated using the following expression:

    m = moles solute / kg solvent (1)

    So in order to calculate the molality of this solution, we need to calculate the moles of the glucose using the expression:

    n = mass / molecular weight (2)

    The molecular weight of glucose, can be calculated using the molecular mass of the atoms in the glucose:

    C = 12 g/mol; H = 1 g/mol; O = 16 g/mol

    the molecular weight is:

    MW = (12*6) + (12*1) + (6*16) = 180 g/mol

    Then, the moles of glucose:

    moles = 50 / 180 = 0.2778 moles

    The solvent in this case is water, and 500 g of water is 0.5 kg of water, so the molality is:

    m = 0.2778 / 0.5

    m = 0.5556 mol/kg
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