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Juliana Holt
Chemistry
20 December, 14:46
500 mL of He at 300 K is heated to 450 K. Find V2
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Rowan Bullock
20 December, 14:58
0
V2 = 0.75 L
Explanation:
assumin ideal gas:
PV = RTn
∴ T1 = 300K
∴ V1 = 0.500 L
∴ T2 = 450 K
⇒ V2 = ?
assuming P, n constant:
⇒ PV1 = RT1n
⇒ V1/T1 = Rn/P = K ... (1)
⇒ V2/T2 = RN/P = K ... (2)
(1) = (2):
⇒ V1/T1 = V2/T2
⇒ V2 = (V1/T1) T2
⇒ V2 = (0.500 L/300 K) (450 K)
⇒ V2 = 0.75 L
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